Swift NSPredicate throwing EXC_BAD_ACCESS(Code=1, address=0x1) when compounding statements

swift core-data nspredicate

4738 просмотра

2 ответа

I am trying to use NSPredicate in Swift to query Core Data but it throws an EXC_BAD_ACCESS(Code=1, address=0x1) error when trying to run it, what am I doing wrong?

Here is the file where the error happens

class LevelsScreenModel : UIViewController {

func getWord(level: Int, section: Int) -> String
    let fetchRequest = NSFetchRequest(entityName: "Words")

    //This is the line where the error happens
    fetchRequest.predicate = NSPredicate(format: "level = %@", level)
    fetchRequest.predicate = NSPredicate(format: "section = %@", section)

    let word = AppDelegate().managedObjectContext!.executeFetchRequest(fetchRequest, error: nil) as [Words]

    if(word.count > 1)
        for words in word
            return words.word

    return "ERROR"
Автор: Cesarg219 Источник Размещён: 12.11.2019 09:40

Ответы (2)

51 плюса


The %@ placeholder in predicate format strings is for Objective-C objects, so you have to wrap the integer into an NSNumber:

fetchRequest.predicate = NSPredicate(format: "level = %@", NSNumber(integer: level))

or use ld instead to format a (long) integer:

fetchRequest.predicate = NSPredicate(format: "level = %ld", level)

Note also that

fetchRequest.predicate = NSPredicate(format: ...)
fetchRequest.predicate = NSPredicate(format: ...)

does not create a compound predicate, the seconds assignment simply overwrites the first. You can use an NSCompoundPredicate:

let p1 = NSPredicate(format: "level = %ld", level)!
let p2 = NSPredicate(format: "section = %ld", section)!
fetchRequest.predicate = NSCompoundPredicate.andPredicateWithSubpredicates([p1, p2])

or simply combine the predicates with "AND":

fetchRequest.predicate = NSPredicate(format: "level = %ld AND section = %ld", level, section)
Автор: Martin R Размещён: 20.02.2015 06:01

-1 плюса

Instead of fussing around with format conversions and AND subpredicates, you could use the PredicatePal framework:

fetchRequest.predicate = *(Key("level") == level && Key("section") == section)

Note that you'll need to use == instead of = for equality comparison.

Автор: Glen Low Размещён: 28.12.2015 05:37
Вопросы из категории :